What were the dimensions of the original photo?O4 inches by 4 inchesO 6 inches by 6 inches10 inches by 10 inches12 inches by 12 inches

Answer: second option.Step-by-step explanation: Given the following equation: [tex](x+10)^2=256[/tex] You need to find the value of "x" in order to find the side measure of the original square photo. Knowing that: [tex](a+b)^2=a^2+2ab+b^2[/tex] You can expand the equation: [tex](x+10)^2=256\\\\x^2+2(x)(10)+10^2=256\\\\x^2+20x+100=256[/tex] The next step is to subtract 256 from both sides of the equation: [tex]x^2+20x+100-256=256-256\\\\x^2+20x-156=0[/tex] Now you can factor the quadratic equation. Find two numbers whose sum is 20 and whose product is -156. These are 26 and 6: [tex](x+26)(x-6)=0\\\\x_1=-26\\\\x_2=6[/tex] Choose the positive value. Therefore, the dimensions of the original  square photo were: [tex]6\ inches\ by\ 6\ inches[/tex]